Step - conjoin

conjoin(delimiter) joins the elements of the list a traverser holds into one string, with delimiter between two elements. null elements are skipped (no delimiter is written for them), and an empty list gives the empty string. The incoming value must be a list (a fold(), a path(), a list constant or property; see List Functions).

graphersal> g.V().values("age").order().fold().conjoin(";")
27;29;32;35

graphersal> g.V("1").out().path().by("name").conjoin(" -> ")
marko -> josh
marko -> lop
marko -> vadas

graphersal> g.inject(["a", (), "b"]).conjoin("+")
a+b

Each element is written as as_string() writes it: numbers (27, 2.5), booleans, UUIDs and strings as their text, a vertex as v[1], an edge as e[7][1-knows->2].

Deviation from TinkerPop

A nested list or a map inside the list has no string form in Graphersal: conjoin() fails with a cast error there, where TinkerPop writes Java's toString text ([a, b], {k=v}). Graphersal never produces Java formats as data text (the same rule as for asString() of a map); unfold or conjoin() the inner list first. No scenario of the TinkerPop suite covers the case.